Write the following situation as integer with appropriate sign.
a bank withdrawal of 500
-500
In a Mathematics test, marks obtained by the 40 students are as follows, arrange them in a table by using the tally marks.
8 1 3 7 6 5 5 4 4 2 4 9 5 3 7 1 6 5 2 7 7 3 8 4 2 8 9 5 8 6 7 4 5 6 9 6 4 4 6 6 |
Also find:
(a) How many students obtained maximum marks.
(b) How many students obtained minimum marks.
(c) How many students obtained marks more than 4.
Marks Obtained | Tally Marks | Number of Students |
1 | || | 2 |
2 | ||| | 3 |
3 | ||| | 3 |
4 | || | 7 |
5 | | | 6 |
6 | || | 7 |
7 | 5 | |
8 | |||| | 4 |
9 | ||| | 3 |
a) 3 students secured maximum marks (frequency of 9 is 3).
b) 2 students secured minimum marks (frequency of 1 is 2).
c) 25 students secured more than 4 marks (Total frequency of 5,6,7,8,9 marks = 6+7+5+4+3= 25).
Days | Monday | Tuesday | Wednesday | Thursday | Friday |
Number of Books Sold | 60 | 55 | 50 | 45 | 30 |
7 X 109
= 7 X (100 + 9)
=7 X 100 + 7 X 9
= 700 + 63
= 763
1 64
2 32
4 16
8 8
The possible factors are 1, 2, 4, 8, 16, 32 and 64
(i) BC
(ii) CD
Draw a number line and represent the following number:
(a) + 8
(b) –10
Each copy has 15 pages.
Hence 13,560 copies = 15 13,560 pages
Therefore,
Everyday 2,03,400 pages are printed.
(25 X 4) X 7896 X (50 X 2)
=100 X 7896 X 100
=78960000
Given no 438750
DIVISIBILITY BY
2 Yes, since units place is even.
4 No, since the number formed by last 2 digits is 50 which is not divisible by 4.
5 Yes, since units place is 0.
a) Name two pairs of opposite sides.
b) Name four pairs of adjacent sides.
c) Name two pairs of opposite angles.
a) PO and MN; PM and ON.
b) OP and PM; PM and MN; MN and NO; NO and OP.
c) P and N; M and O.
(i) 6 sides, Hexagon (ii) 8 sides, Octagon
(-3) + (-7) = -10
(-7) - (-3) = -7 + 3 = -4
-10 < -4
Therefore, (-3) + (-7) < (-7) - (-3)
In a Mathematics test, marks obtained by the 40 students are as follows, arrange them in a table by using the tally marks.
8 1 3 7 6 5 5 4 4 2 4 9 5 3 7 1 6 5 2 7 7 3 8 4 2 8 9 5 8 6 7 4 5 6 9 6 4 4 6 6 |
Also find:
(a) How many students obtained maximum marks.
(b) How many students obtained minimum marks.
(c) How many students obtained marks more than 4.
Marks Obtained | Tally Marks | Number of Students |
1 | || | 2 |
2 | ||| | 3 |
3 | ||| | 3 |
4 | || | 7 |
5 | | | 6 |
6 | || | 7 |
7 | 5 | |
8 | |||| | 4 |
9 | ||| | 3 |
a) 3 students secured maximum marks (frequency of 9 is 3).
b) 2 students secured minimum marks (frequency of 1 is 2).
c) 25 students secured more than 4 marks (Total frequency of 5,6,7,8,9 marks = 6+7+5+4+3= 25).
2 | 20, 40, 75 |
2 | 10, 20, 75 |
2 | 5, 10 75 |
5 | 5, 5 75 |
5 | 1 1, 15 |
3 | 1, 1, 3 |
1, 1, 1 |
LCM = 2 2 2 5 5 3 = 600
Least 5 digit number = 10000
16
600) 10000
600
4000
3600
400
Since remainder is 400 it needs 200 more, to be fully divisible by 600.
Required no = 10000 + (200 + 9)[We need the number that leaves remainer 9]
= 10209
(i) Sum of two integers = – 20
One integer = 20
Second integer = – 20 – 20
= – 40
(ii) Sum of two integers = 147
One integer = – 59
Second integer = 147 – (– 59)
= 147 + 59
= 206
Days | Monday | Tuesday | Wednesday | Thursday | Friday |
Number of Books Sold | 60 | 55 | 50 | 45 | 30 |
Write the following situation as integer with appropriate sign.
a bank withdrawal of 500
-500
In a Mathematics test, marks obtained by the 40 students are as follows, arrange them in a table by using the tally marks.
8 1 3 7 6 5 5 4 4 2 4 9 5 3 7 1 6 5 2 7 7 3 8 4 2 8 9 5 8 6 7 4 5 6 9 6 4 4 6 6 |
Also find:
(a) How many students obtained maximum marks.
(b) How many students obtained minimum marks.
(c) How many students obtained marks more than 4.
Marks Obtained | Tally Marks | Number of Students |
1 | || | 2 |
2 | ||| | 3 |
3 | ||| | 3 |
4 | || | 7 |
5 | | | 6 |
6 | || | 7 |
7 | 5 | |
8 | |||| | 4 |
9 | ||| | 3 |
a) 3 students secured maximum marks (frequency of 9 is 3).
b) 2 students secured minimum marks (frequency of 1 is 2).
c) 25 students secured more than 4 marks (Total frequency of 5,6,7,8,9 marks = 6+7+5+4+3= 25).
Days | Monday | Tuesday | Wednesday | Thursday | Friday |
Number of Books Sold | 60 | 55 | 50 | 45 | 30 |
7 X 109
= 7 X (100 + 9)
=7 X 100 + 7 X 9
= 700 + 63
= 763
1 64
2 32
4 16
8 8
The possible factors are 1, 2, 4, 8, 16, 32 and 64
(i) BC
(ii) CD
Draw a number line and represent the following number:
(a) + 8
(b) –10
Each copy has 15 pages.
Hence 13,560 copies = 15 13,560 pages
Therefore,
Everyday 2,03,400 pages are printed.
(25 X 4) X 7896 X (50 X 2)
=100 X 7896 X 100
=78960000
Given no 438750
DIVISIBILITY BY
2 Yes, since units place is even.
4 No, since the number formed by last 2 digits is 50 which is not divisible by 4.
5 Yes, since units place is 0.
a) Name two pairs of opposite sides.
b) Name four pairs of adjacent sides.
c) Name two pairs of opposite angles.
a) PO and MN; PM and ON.
b) OP and PM; PM and MN; MN and NO; NO and OP.
c) P and N; M and O.
(i) 6 sides, Hexagon (ii) 8 sides, Octagon
(-3) + (-7) = -10
(-7) - (-3) = -7 + 3 = -4
-10 < -4
Therefore, (-3) + (-7) < (-7) - (-3)
In a Mathematics test, marks obtained by the 40 students are as follows, arrange them in a table by using the tally marks.
8 1 3 7 6 5 5 4 4 2 4 9 5 3 7 1 6 5 2 7 7 3 8 4 2 8 9 5 8 6 7 4 5 6 9 6 4 4 6 6 |
Also find:
(a) How many students obtained maximum marks.
(b) How many students obtained minimum marks.
(c) How many students obtained marks more than 4.
Marks Obtained | Tally Marks | Number of Students |
1 | || | 2 |
2 | ||| | 3 |
3 | ||| | 3 |
4 | || | 7 |
5 | | | 6 |
6 | || | 7 |
7 | 5 | |
8 | |||| | 4 |
9 | ||| | 3 |
a) 3 students secured maximum marks (frequency of 9 is 3).
b) 2 students secured minimum marks (frequency of 1 is 2).
c) 25 students secured more than 4 marks (Total frequency of 5,6,7,8,9 marks = 6+7+5+4+3= 25).
2 | 20, 40, 75 |
2 | 10, 20, 75 |
2 | 5, 10 75 |
5 | 5, 5 75 |
5 | 1 1, 15 |
3 | 1, 1, 3 |
1, 1, 1 |
LCM = 2 2 2 5 5 3 = 600
Least 5 digit number = 10000
16
600) 10000
600
4000
3600
400
Since remainder is 400 it needs 200 more, to be fully divisible by 600.
Required no = 10000 + (200 + 9)[We need the number that leaves remainer 9]
= 10209
(i) Sum of two integers = – 20
One integer = 20
Second integer = – 20 – 20
= – 40
(ii) Sum of two integers = 147
One integer = – 59
Second integer = 147 – (– 59)
= 147 + 59
= 206
Days | Monday | Tuesday | Wednesday | Thursday | Friday |
Number of Books Sold | 60 | 55 | 50 | 45 | 30 |
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