Chemistry:2011:CBSE:[All India]:Set-II

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  • Q1

    What is meant by ‘lanthanoid contraction’?

    Marks:1
    Answer:

    There is a gradual decrease in atomic and ionic radii of lanthanoids (from lanthanum to lutetium) with an increase in atomic number. This is known as ‘lanthanoid contraction’.

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  • Q2

    Draw the structure of 4-chloropentan-2-one.

    Marks:1
    Answer:

    The structure of 4-chloropentan-2-one is as follows:

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  • Q3

    Define order of a reaction.

    Marks:1
    Answer:

    Order of a reaction is the sum of the exponents to which the concentration terms are raised in the rate law expression.

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  • Q4

    Rearrange the following in an increasing order of their basic strengths: 
    C6H5NH2, C6H5N(CH3)2 (C6H5)2NH and CH3NH2

    Marks:1
    Answer:

    (C6H5)2NH < C6H5NH2 < C6H5N(CH3)2 < CH3NH2

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  • Q5

     What are lyophobic colloids? Give one example for them.

    Marks:1
    Answer:

    The colloidal systems in which the particles of dispersed phase have no or very little affinity for the dispersion medium are called lyophobic colloids.

    Example: sols of silica, silver iodide, metal sulphides.

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  • Q6

    Why is it that only sulphide ores are concentrated by ‘froath floatation process’?

    Marks:1
    Answer:

    Only sulphide ores are concentrated by froth floatation process because the surface of sulphide ores is preferentially wetted by oils while that of gangue is preferentially wetted by water.

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  • Q7

     Write the IUPAC name of the following compound:

    Marks:1
    Answer:

    3-Bromo-2-methyl-propene

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  • Q8

    Draw the structure of 2,6-Dimethylphenol.

    Marks:1
    Answer:

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  • Q9

    Calculate the packing efficiency of a metal crystal for a simple cubic lattice.

    Marks:2
    Answer:

    In a simple cubic lattice, the particles are located only at the corners of the cube and touch each other along the edge.
                  

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  • Q10

    The thermal decomposition of HCOOH is a first order reaction with a rate constant of 2.4 × 10–3 s–1 at a certain temperature. Calculate how long will it take for three-fourths of initial quantity of HCO2H to decompose. (log 0.25 = – 0.6021)

    Marks:2
    Answer:

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