Chemistry:2005:CBSE:[Delhi]:Set-II

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  • Q1

    Express the relation between the half-life period of a reactant and its initial concentration if the reaction involved is of second order.

    Marks:1
    Answer:

    The relation between the half-life period of a reactant and its initial concentration of second order  reaction is:
                  

     Half life  1/ Initial concentration of reactant

     
     

     

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  • Q2

    State the formula relating pressure of a gas with its mole fraction in a liquid solution in contact with it.

    Marks:1
    Answer:

    This relation is given by Henry:-
    p = KH x XA
    Where p = Vapour pressure of the gas

    KH = Henry’s constant

    XA = Mole fraction of gas in liquid.

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  • Q3

    What is the maximum possible coordination number of an atom in an hcp crystal structure of an element?

    Marks:1
    Answer:

    The maximum possible coordination number of an atom in an hcp crystal structure of an element is 12.

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  • Q4

    Why primary amines have higher boiling than tertiary amines.

    Marks:1
    Answer:

    Primary amines have higher boiling point than tertiary amines because primary amines form intermolecular hydrogen bonding but tertiary amines do not form intermolecular hydrogen bonding due to absence of hydrogen atom.

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  • Q5

    How are formalin and trioxane related to methanal?

    Marks:1
    Answer:

    Formalin:- It is a 40% aqueous solution of methanal.
    Trioxane:-  It is a trimer of methanal and it is also known as metaformaldehyde.

     

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  • Q6

    On the basis of Heisenberg Uncertainty Principle show that the electron (mass=9 x 10 -31 kg) cannot exist within an atomic nucleus of radius 10 -15 m. out of syllabus

    Marks:2
    Answer:

    This question is not in 2007-2008 syllabus.

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  • Q7

    Show that the Heisenberg Uncertainty Principle is of negligible significance for an object of 10 -6 kg mass.       

    h/ 4 = 0.528  10-34 kg m2s-1 

    Out of syllabus

    Marks:2
    Answer:

    This question is not in 2007-2008 syllabus.

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  • Q8

    Write one chemical reaction each to show that
    (a) Tin (II) chloride is a reducing agent.
    (b) Chlorine gas can be obtained from bleaching powder.

    Marks:2
    Answer:

    a) Tin (II) chloride is a reducing agent:
    2FeCl3 + SnCl2 SnCl4 + 2FeCl2
    (b) Chlorine gas can be obtained from bleaching powder:
    Ca(OCl)Cl + 4HCl  CaCl2 + 2H2O + 2Cl2

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  • Q9

    Describe the steps involved in the preparation of either potassium dichromate from sodium chromate or potassium permanganate from manganese dioxide.

    Marks:2
    Answer:

     

    Preparation of Potassium dichromate from sodium chromate:-In this preparation three steps are involved and these steps are:-
    (i)  Preparation of sodium chromate:- Finely powdered chromite ore is mixed with soda ash and quicklime. The mixture is then roasted in a reverberatory furnace in the presence of air. Yellow mass due to the formation of sodium chromate is obtained.

    4 Fe2Cr2O4 +  O2  2 Fe2O3   + 4 Cr2O3
    4 Cr2O3 + 8 Na2CO3 + 6 O2 8 Na2Cr2O4 + 8 CO2

    4 Fe2Cr2O4+ 7 O2 + 8Na2CO2Fe2O3+8 CO2 + 8 Na2Cr2O4 

    (ii) Conversion of chromate into dichromate:- The yellow solution of Chromate is filtered and treated with  concentrated sulphuric acid to give a solution from which orange sodium dichromate (Na2Cr2O7.2H2O) can be crystalized. 

    2 Na2Cr2O4 + H2SONa2Cr2O7 + Na2SO4 + H2O

    Sodium Chromate          Sodium dichromate

    (iii) Conversion of sodium dichromate to potassium dichromate:- Hot concentrated solution of sodium dichromate is treated with a calculated amount of potassium chloride, when potassium dichromate being less soluble crystallizes out on cooling.

    Na2Cr2O7  +   2KCl     K2Cr2O7 + 2NaCl





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  • Q10

    What are enantiomers and diastereomers? Differentiate between chiral and achiral molecules.

    Marks:2
    Answer:

    Enantiomers:- Stereoisomers which are non-superimposable mirror images to each other are known as enantiomers or enantiomorphs.

    Diastereomers:- The stereoisomers which are optically active isomers but not the mirror images of each other are called diastereoisomers.

    An object which is not superimposable on its mirror image is said to be chiral whereas the object which are superimposable on its mirror image is said to be achiral.

     

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