CBSE Delhi-Set-3-2008

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  • Q1

    What is the direction of the force acting on a charged particle q, moving with a velocity  in a uniform magnetic field ?

    Marks:1
    Answer:

    The force is given by

    This force is right angles to  & .

     

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  • Q2

    Name the absorbing material used to control the reaction rate of neutrons in a nuclear reactor.

    Marks:1
    Answer:

    Cadmium rods are the absorbing material used to control the reaction rate of neutrons in a nuclear reactor.

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  • Q3

    State the reason, why two independent sources of light cannot be considered as coherent sources.

    Marks:1
    Answer:

    Because, they will produce the phase difference and produce interference.

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  • Q4

    Name the part of the electromagnetic spectrum of wavelength 10-2m and mention its one application.

    Marks:1
    Answer:

    Microwaves. It is used in radar & communication purposes.

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  • Q5

    An electron and a proton have the same de-Broglie wavelength associated with them. How are their kinetic energies related to each other?

    Marks:1
    Answer:

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  • Q6

    A 500 charge is at the center of a square of side 10 cm. Find the work done in moving a charge of 10 C between two diagonally opposite points on the square.

    Marks:1
    Answer:

    According to the given condition, we have

     

    VOA = VOB

    Therefore,  work done is given by

    W = q( VOB - VOA)

    Hence, W is zero.

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  • Q7

    How does the power of a convex lens vary, if the incident red light is replaced by violet light?

    Marks:1
    Answer:

    The power increases because the refractive index of a material is more for violet colour.

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  • Q8

    The plot of the variation of potential difference across a combination of three identical cells in series, versus current is as shown below. What is the emf of each cell?

    Marks:1
    Answer:

    Since all the cells are connected in series so current flowing through each cell is same. Therefore total resistance given by 
    Rt = 6/1 = 6
    Internal resistance of each cell is 6/3 = 2
    Now e.m.f. of each cell is  = 2 x 1A = 2 volts

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  • Q9

    Draw a ray diagram of a compound microscope. Write the expression for its magnifying power.

    Marks:2
    Answer:

    Ray diagram for the formation of image in a compound microscope

    Magnifying power:- M = (L/f0) (1 + D/fe)
    Where M = Magnifying power.

                L   = Length of microscope tube (= v).

                fo   = Focal length of objective lens.

                D   = Least distance of distinct vision.

                fe   = Focal length of eye piece.

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  • Q10

    A ray of light passing through an equilateral triangular glass prism from air undergoes minimum deviation when angle of incidence is 3/4th of the angle of prism. Calculate the speed of light in the prism.

    Marks:2
    Answer:

    We have,
    A= 600
    i1= i2 = (3/4)A = 450  (according to given condition)
    Determining the value of ,
    A + = i1+i2.

    or 600 = 450+450.

    = 900 - 600 = 300.

    The speed of light is given by,

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