CBSE [Delhi]_X_Mathematics_2015_Set III
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Q1
In Fig. 1, PA and PB are tangents to the circle with centre O such that ∠APB=50o. Write the measure of∠OAB.
Marks:1View AnswerAnswer:
Join OC.
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Q2
Marks:1View AnswerAnswer:
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Q3
The tops of two towers of height x and y, standing on level ground, subtend angles of 30° and 60° respectively at the centre of the line joining their feet, then find x:y.
Marks:1View AnswerAnswer:
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Q4
A letter of English alphabet is chosen at random. Determine the probability that the chosen letter is a constant.
Marks:1View AnswerAnswer:
Number of English alphabet = 26
Number of constants = 21Probability of choosing a constant = 21/26
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Q5
From a point T outside a circle of centre O, tangents TP and TQ are drawn to the circle. Prove that OT is the right bisector of line segment PQ.
Marks:2View AnswerAnswer:
Given: TP and TQ are tangents to circle and OT intersects chord PQ at R.
To Prove: OT bisects PQ at right angle.
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Q6
Find the middle term of the A.P.
6, 13, 20, …, 216.Marks:2View AnswerAnswer:
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Q7
In Fig. 2, AB is the diameter of a circle with centre O and AT is a tangent. If
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Marks:2View AnswerAnswer:
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Q8
If A(5, 2), B(2,–2) and C(–2, t) are the vertices of a right angled triangle with angle B = 90°, then find the value of t.
Marks:2View AnswerAnswer:
In right angled triangle, ABC,
By Pythagoras Theorem,
AC2 = AB2 + BC2
(5 + 2)2 +(2 – t)2 =(5 – 2)2 +(2 +2)2 +(2 + 2)2
+(–2 – t)272 + 4 – 4t + t2 = 9 + 16 + 16 + 4 + 4t + t2
53 – 4t = 45 + 4t
53 – 45 = 8t
t = 8/8 = 1 -
Q9
Marks:2View AnswerAnswer:
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Q10
Solve the following quadratic equation for x:
9x2 – 6b2x – (a4 – b4) = 0
Marks:2View AnswerAnswer:
