CBSE [ Delhi ]_X_Mathematics_2009_Set III

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  • Q1

    In figure, CP and CQ are tangents to a circle with centre O. ARB is another tangent touching the circle at R. If CP = 11 cm, and BC = 7 cm, then find the length of BR.

    Marks:1
    Answer:

    Given, CP and CQ are tangents from point C.
    Therefore,
                  CP = CQ = 11 cm 
    Also,
              BQ = BR
              BQ = CQ – BC
                    = (11-7) cm
                    = 4 cm
           BR = 4 cm.

     

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  • Q2

    For what value of p, are 2p – 1, 7 and 3p three consecutive terms of an A.P. ?

    Marks:1
    Answer:

    Given, 2p – 1, 7 and 3p are in A.P, then

    7 - (2p - 1) = 3p - 7
    7 - 2p + 1 = 3p - 7
    5p = 8 + 7
    p = 3

     

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  • Q3

    The decimal expansion of the rational number will terminate after how many places of decimals?

    Marks:1
    Answer:

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  • Q4

    In the given figure, M = N = 46°. Express x in terms of a, b and c where a, b and c are lengths of LM, MN and NK respectively.

    Marks:1
    Answer:

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  • Q5

    Marks:1
    Answer:

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  • Q6

    Find the value of a so that point (3, a) lies on the line represented by 2x - 3y = 5.

    Marks:1
    Answer:

    Since Point (3, a) lies on the line 2x – 3y = 5, so it will satisfy the equation of line.
    Hence, 2(3) – 3(a) = 5
    Or,           6 – 3a = 5
    Or,                3a = 1
                    a = 1/3

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  • Q7

    A cylinder and a cone are of same base radius and of same height. Find the ratio of the volume of cylinder to that of the cone.

    Marks:1
    Answer:

    Given,
    Radius of cylinder = Radius of cone = r (say)
    Height of cylinder = Height of cone = h (say)
     Volume of cylinder / Volume of cone = r²h/(1/3)r²h = 1/(1/3) = 3 : 1

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  • Q8

    Find the distance between the points .

    Marks:1
    Answer:

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  • Q9

    Write the median class of the following distribution:
    Classes          Frequency
    0 – 10                  4
    10 – 20                4
    20 – 30                8
    30 – 40                10
    40 – 50                12
    50 – 60                 8
    60 – 70                 4

    Marks:1
    Answer:

    Classes

    Frequency    

    Cumulative frequency

    0 – 10

           4

    4

    10 – 20

           4

    8

    20 – 30

           8

    16

    30 – 40

           10

    26

    40 – 50

           12

    38

    50 – 60

            8

    46

    60 – 70

            4

    50

    Total number of observations (n) = 50.
    So, n/2 = 25. 
    The cumulative frequency 26 is just greater than n/2 = 25.
    So, 30 – 40 is the median class.

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  • Q10

    For what value of p, (-4) is a zero of the polynomial x2 – 2x – (7p + 3) ?

    Marks:1
    Answer:

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