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CBSE [ All India ]_X_Mathematics_2009_Set II

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  • Q1

    Find the [ HCF x LCM ] for the numbers 105 and 120.

    Marks:1
    Answer:

    Since,
       HCF  LCM = Product of numbers

                           = 105  120

                           = 12600

    HCF  LCM = 12600

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  • Q2

    Find the number of solutions of the following pair of linear equations :
    x + 2y – 8 = 0
    2x + 4y = 16

    Marks:1
    Answer:

     

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  • Q3

    If 4/5, a, 2 are three consecutive terms of an A.P., then find the value of a.

    Marks:1
    Answer:

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  • Q4

    Two coins are tossed simultaneously. Find the probability of getting exactly one head.

    Marks:1
    Answer:

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  • Q5

    In figure,  ABC is circumscribing a circle. Find the length of BC. 

    Marks:1
    Answer:

    From the given figure, we have

    BP =  BR = 3 cm

    CQ = AC - AQ = (11 - 4) cm = 7 cm [AQ = QR]

    Now, BC = BP + PC = (3 + 7) cm = 10 cm [PC = CQ].

     

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  • Q6

    If the diameter of a semicircular protractor is 14 cm, then find its perimeter.

    Marks:1
    Answer:

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  • Q7

    If 1 is a zero of the polynomial p(x) = ax2 – 3 (a – 1) x –1, then find the value of a.

    Marks:1
    Answer:

    If 1 is the zero of the polynomial, then
           p(1) = 0
       p(1) = a(1)2 – 3 (a – 1) 1 –1 = 0
                 a – 3a + 3 –1 = 0
               –2a = –2
                    a = 1

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  • Q8


    Marks:1
    Answer:

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  • Q9

    Marks:1
    Answer:

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  • Q10

    Find the discriminant of the quadratic equation

    Marks:1
    Answer:

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