CBSE [ All India]_X_Mathematics_2006_Set I
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Q1
A man borrows Rs. 25,200 from a finance company and has to repay it in two equal annual installments. If the interest is charged at the rate of 10% per annum compounded annually, calculate the amount of installment. Marks:3Answer:
Now, out of Syllabus -
Q2
If (x + 2) (x - 3) is the HCF of the polynomials p(x) = (x2 + x - 2) (3x2 - 8x + c) and q(x) = (x2 + x - 12) (2x2 + x + b). Find the values of c and b. Marks:3Answer:
Now out of syllabus -
Q3
The sum of the digits of a two-digit number is 12. The number obtained by interchanging the two digits exceeds the given number by 18. Find the number. Marks:3Answer:
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Q4
Solve the system of equations:
bx/a - ay/b + a + b = 0 and bx - ay + 2ab = 0Marks:3Answer:
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Q5
Using the quadratic formula, solve the equation:
a2b2 x2 – (4b4 – 3a4 )x – 12a2 b2 = 0 Marks:3Answer:
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Q6
Marks:3Answer:
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Q7
The sum of two natural numbers is 8. Determine the numbers if the sum of their reciprocals is 8/15.
Marks:3Answer:
let one umber be x, other will be 8 - x
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Q8
The 5th term of an Arithmetic Progression (A.P.) is 26 and the 10th term is 51. Determine the 15th term of the A.P. Marks:3Answer:
Let Ist terms of A.P = a and common difference be d 5th term = a+4d = 26 10th term = a+9d = 51 a + 4d = 26 a + 9d = 51 on subtracting 5d = 25 d = 5 putting the value of d in Ist a+4d = 26 a+20 = 26 a = 6 first term = 6 15th term = a+14d 6+14(5) 6+70 = 76 -
Q9
Find the sum of all the natural numbers less than 100 which are divisible by 6. Marks:3Answer:
Series of natural numbers which are divisible by 6 6, 12, 18…96 First term a = 6 Last term l = 96 Common difference d = 6 Number of terms = 96/6 = 16 Sn = n/2(a+l) =16/2(6+96) =8(102) S16 =816 -
Q10
A household article is available for Rs. 970 cash or Rs. 210 cash down payment followed by three equal monthly installments. If the rate of interest charged under the installment plan is 16% per annum, find the amount of installment. Marks:3Answer:
Now, out of syllabus